3.219 \(\int \frac {(h+i x) (a+b \log (c (d+e x)^n))}{f+g x} \, dx\)

Optimal. Leaf size=119 \[ \frac {(g h-f i) \log \left (\frac {e (f+g x)}{e f-d g}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{g^2}+\frac {a i x}{g}+\frac {b i (d+e x) \log \left (c (d+e x)^n\right )}{e g}+\frac {b n (g h-f i) \text {Li}_2\left (-\frac {g (d+e x)}{e f-d g}\right )}{g^2}-\frac {b i n x}{g} \]

[Out]

a*i*x/g-b*i*n*x/g+b*i*(e*x+d)*ln(c*(e*x+d)^n)/e/g+(-f*i+g*h)*(a+b*ln(c*(e*x+d)^n))*ln(e*(g*x+f)/(-d*g+e*f))/g^
2+b*(-f*i+g*h)*n*polylog(2,-g*(e*x+d)/(-d*g+e*f))/g^2

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Rubi [A]  time = 0.14, antiderivative size = 119, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 6, integrand size = 27, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.222, Rules used = {2418, 2389, 2295, 2394, 2393, 2391} \[ \frac {b n (g h-f i) \text {PolyLog}\left (2,-\frac {g (d+e x)}{e f-d g}\right )}{g^2}+\frac {(g h-f i) \log \left (\frac {e (f+g x)}{e f-d g}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{g^2}+\frac {a i x}{g}+\frac {b i (d+e x) \log \left (c (d+e x)^n\right )}{e g}-\frac {b i n x}{g} \]

Antiderivative was successfully verified.

[In]

Int[((h + i*x)*(a + b*Log[c*(d + e*x)^n]))/(f + g*x),x]

[Out]

(a*i*x)/g - (b*i*n*x)/g + (b*i*(d + e*x)*Log[c*(d + e*x)^n])/(e*g) + ((g*h - f*i)*(a + b*Log[c*(d + e*x)^n])*L
og[(e*(f + g*x))/(e*f - d*g)])/g^2 + (b*(g*h - f*i)*n*PolyLog[2, -((g*(d + e*x))/(e*f - d*g))])/g^2

Rule 2295

Int[Log[(c_.)*(x_)^(n_.)], x_Symbol] :> Simp[x*Log[c*x^n], x] - Simp[n*x, x] /; FreeQ[{c, n}, x]

Rule 2389

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.), x_Symbol] :> Dist[1/e, Subst[Int[(a + b*Log[c*
x^n])^p, x], x, d + e*x], x] /; FreeQ[{a, b, c, d, e, n, p}, x]

Rule 2391

Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_.))]/(x_), x_Symbol] :> -Simp[PolyLog[2, -(c*e*x^n)]/n, x] /; FreeQ[{c, d,
e, n}, x] && EqQ[c*d, 1]

Rule 2393

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))]*(b_.))/((f_.) + (g_.)*(x_)), x_Symbol] :> Dist[1/g, Subst[Int[(a +
b*Log[1 + (c*e*x)/g])/x, x], x, f + g*x], x] /; FreeQ[{a, b, c, d, e, f, g}, x] && NeQ[e*f - d*g, 0] && EqQ[g
+ c*(e*f - d*g), 0]

Rule 2394

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))/((f_.) + (g_.)*(x_)), x_Symbol] :> Simp[(Log[(e*(f +
g*x))/(e*f - d*g)]*(a + b*Log[c*(d + e*x)^n]))/g, x] - Dist[(b*e*n)/g, Int[Log[(e*(f + g*x))/(e*f - d*g)]/(d +
e*x), x], x] /; FreeQ[{a, b, c, d, e, f, g, n}, x] && NeQ[e*f - d*g, 0]

Rule 2418

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.)*(RFx_), x_Symbol] :> With[{u = ExpandIntegrand[
(a + b*Log[c*(d + e*x)^n])^p, RFx, x]}, Int[u, x] /; SumQ[u]] /; FreeQ[{a, b, c, d, e, n}, x] && RationalFunct
ionQ[RFx, x] && IntegerQ[p]

Rubi steps

\begin {align*} \int \frac {(h+219 x) \left (a+b \log \left (c (d+e x)^n\right )\right )}{f+g x} \, dx &=\int \left (\frac {219 \left (a+b \log \left (c (d+e x)^n\right )\right )}{g}+\frac {(-219 f+g h) \left (a+b \log \left (c (d+e x)^n\right )\right )}{g (f+g x)}\right ) \, dx\\ &=\frac {219 \int \left (a+b \log \left (c (d+e x)^n\right )\right ) \, dx}{g}+\frac {(-219 f+g h) \int \frac {a+b \log \left (c (d+e x)^n\right )}{f+g x} \, dx}{g}\\ &=\frac {219 a x}{g}-\frac {(219 f-g h) \left (a+b \log \left (c (d+e x)^n\right )\right ) \log \left (\frac {e (f+g x)}{e f-d g}\right )}{g^2}+\frac {(219 b) \int \log \left (c (d+e x)^n\right ) \, dx}{g}+\frac {(b e (219 f-g h) n) \int \frac {\log \left (\frac {e (f+g x)}{e f-d g}\right )}{d+e x} \, dx}{g^2}\\ &=\frac {219 a x}{g}-\frac {(219 f-g h) \left (a+b \log \left (c (d+e x)^n\right )\right ) \log \left (\frac {e (f+g x)}{e f-d g}\right )}{g^2}+\frac {(219 b) \operatorname {Subst}\left (\int \log \left (c x^n\right ) \, dx,x,d+e x\right )}{e g}+\frac {(b (219 f-g h) n) \operatorname {Subst}\left (\int \frac {\log \left (1+\frac {g x}{e f-d g}\right )}{x} \, dx,x,d+e x\right )}{g^2}\\ &=\frac {219 a x}{g}-\frac {219 b n x}{g}+\frac {219 b (d+e x) \log \left (c (d+e x)^n\right )}{e g}-\frac {(219 f-g h) \left (a+b \log \left (c (d+e x)^n\right )\right ) \log \left (\frac {e (f+g x)}{e f-d g}\right )}{g^2}-\frac {b (219 f-g h) n \text {Li}_2\left (-\frac {g (d+e x)}{e f-d g}\right )}{g^2}\\ \end {align*}

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Mathematica [A]  time = 0.12, size = 110, normalized size = 0.92 \[ \frac {(g h-f i) \log \left (\frac {e (f+g x)}{e f-d g}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )+a g i x+\frac {b g i (d+e x) \log \left (c (d+e x)^n\right )}{e}+b n (g h-f i) \text {Li}_2\left (\frac {g (d+e x)}{d g-e f}\right )-b g i n x}{g^2} \]

Antiderivative was successfully verified.

[In]

Integrate[((h + i*x)*(a + b*Log[c*(d + e*x)^n]))/(f + g*x),x]

[Out]

(a*g*i*x - b*g*i*n*x + (b*g*i*(d + e*x)*Log[c*(d + e*x)^n])/e + (g*h - f*i)*(a + b*Log[c*(d + e*x)^n])*Log[(e*
(f + g*x))/(e*f - d*g)] + b*(g*h - f*i)*n*PolyLog[2, (g*(d + e*x))/(-(e*f) + d*g)])/g^2

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fricas [F]  time = 0.45, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {a i x + a h + {\left (b i x + b h\right )} \log \left ({\left (e x + d\right )}^{n} c\right )}{g x + f}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((i*x+h)*(a+b*log(c*(e*x+d)^n))/(g*x+f),x, algorithm="fricas")

[Out]

integral((a*i*x + a*h + (b*i*x + b*h)*log((e*x + d)^n*c))/(g*x + f), x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (i x + h\right )} {\left (b \log \left ({\left (e x + d\right )}^{n} c\right ) + a\right )}}{g x + f}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((i*x+h)*(a+b*log(c*(e*x+d)^n))/(g*x+f),x, algorithm="giac")

[Out]

integrate((i*x + h)*(b*log((e*x + d)^n*c) + a)/(g*x + f), x)

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maple [C]  time = 0.32, size = 750, normalized size = 6.30 \[ \frac {i \pi b f i \,\mathrm {csgn}\left (i c \right ) \mathrm {csgn}\left (i \left (e x +d \right )^{n}\right ) \mathrm {csgn}\left (i c \left (e x +d \right )^{n}\right ) \ln \left (g x +f \right )}{2 g^{2}}-\frac {a f i \ln \left (g x +f \right )}{g^{2}}+\frac {a h \ln \left (g x +f \right )}{g}+\frac {b i x \ln \left (\left (e x +d \right )^{n}\right )}{g}+\frac {i \pi b f i \mathrm {csgn}\left (i c \left (e x +d \right )^{n}\right )^{3} \ln \left (g x +f \right )}{2 g^{2}}+\frac {i \pi b h \,\mathrm {csgn}\left (i c \right ) \mathrm {csgn}\left (i c \left (e x +d \right )^{n}\right )^{2} \ln \left (g x +f \right )}{2 g}+\frac {b d i n \ln \left (d g -e f +\left (g x +f \right ) e \right )}{e g}+\frac {b f i n \ln \left (\frac {d g -e f +\left (g x +f \right ) e}{d g -e f}\right ) \ln \left (g x +f \right )}{g^{2}}-\frac {b h n \dilog \left (\frac {d g -e f +\left (g x +f \right ) e}{d g -e f}\right )}{g}+\frac {b h \ln \left (\left (e x +d \right )^{n}\right ) \ln \left (g x +f \right )}{g}-\frac {b f i \ln \relax (c ) \ln \left (g x +f \right )}{g^{2}}+\frac {i \pi b i x \,\mathrm {csgn}\left (i \left (e x +d \right )^{n}\right ) \mathrm {csgn}\left (i c \left (e x +d \right )^{n}\right )^{2}}{2 g}+\frac {i \pi b h \,\mathrm {csgn}\left (i \left (e x +d \right )^{n}\right ) \mathrm {csgn}\left (i c \left (e x +d \right )^{n}\right )^{2} \ln \left (g x +f \right )}{2 g}+\frac {i \pi b i x \,\mathrm {csgn}\left (i c \right ) \mathrm {csgn}\left (i c \left (e x +d \right )^{n}\right )^{2}}{2 g}+\frac {b f i n \dilog \left (\frac {d g -e f +\left (g x +f \right ) e}{d g -e f}\right )}{g^{2}}-\frac {b f i n}{g^{2}}+\frac {b h \ln \relax (c ) \ln \left (g x +f \right )}{g}+\frac {b i x \ln \relax (c )}{g}-\frac {i \pi b f i \,\mathrm {csgn}\left (i c \right ) \mathrm {csgn}\left (i c \left (e x +d \right )^{n}\right )^{2} \ln \left (g x +f \right )}{2 g^{2}}-\frac {i \pi b f i \,\mathrm {csgn}\left (i \left (e x +d \right )^{n}\right ) \mathrm {csgn}\left (i c \left (e x +d \right )^{n}\right )^{2} \ln \left (g x +f \right )}{2 g^{2}}-\frac {i \pi b h \,\mathrm {csgn}\left (i c \right ) \mathrm {csgn}\left (i \left (e x +d \right )^{n}\right ) \mathrm {csgn}\left (i c \left (e x +d \right )^{n}\right ) \ln \left (g x +f \right )}{2 g}-\frac {i \pi b i x \,\mathrm {csgn}\left (i c \right ) \mathrm {csgn}\left (i \left (e x +d \right )^{n}\right ) \mathrm {csgn}\left (i c \left (e x +d \right )^{n}\right )}{2 g}+\frac {a i x}{g}-\frac {i \pi b h \mathrm {csgn}\left (i c \left (e x +d \right )^{n}\right )^{3} \ln \left (g x +f \right )}{2 g}-\frac {i \pi b i x \mathrm {csgn}\left (i c \left (e x +d \right )^{n}\right )^{3}}{2 g}-\frac {b f i \ln \left (\left (e x +d \right )^{n}\right ) \ln \left (g x +f \right )}{g^{2}}-\frac {b h n \ln \left (\frac {d g -e f +\left (g x +f \right ) e}{d g -e f}\right ) \ln \left (g x +f \right )}{g}-\frac {b i n x}{g} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((i*x+h)*(b*ln(c*(e*x+d)^n)+a)/(g*x+f),x)

[Out]

1/2*I*b*Pi*csgn(I*c)*csgn(I*(e*x+d)^n)*csgn(I*c*(e*x+d)^n)/g^2*ln(g*x+f)*f*i-a/g^2*ln(g*x+f)*f*i+a/g*ln(g*x+f)
*h+b*ln((e*x+d)^n)*i/g*x+b/e*n/g*i*d*ln(d*g-e*f+(g*x+f)*e)+b*n/g^2*ln(g*x+f)*ln((d*g-e*f+(g*x+f)*e)/(d*g-e*f))
*f*i+b*ln((e*x+d)^n)/g*ln(g*x+f)*h-1/2*I*b*Pi*csgn(I*c)*csgn(I*(e*x+d)^n)*csgn(I*c*(e*x+d)^n)*i/g*x-1/2*I*b*Pi
*csgn(I*(e*x+d)^n)*csgn(I*c*(e*x+d)^n)^2/g^2*ln(g*x+f)*f*i-b*ln(c)/g^2*ln(g*x+f)*f*i-b*n/g^2*i*f+b*ln(c)/g*ln(
g*x+f)*h+b*ln(c)*i/g*x-1/2*I*b*Pi*csgn(I*c)*csgn(I*(e*x+d)^n)*csgn(I*c*(e*x+d)^n)/g*ln(g*x+f)*h-1/2*I*b*Pi*csg
n(I*c)*csgn(I*c*(e*x+d)^n)^2/g^2*ln(g*x+f)*f*i+1/2*I*b*Pi*csgn(I*c*(e*x+d)^n)^3/g^2*ln(g*x+f)*f*i-b*n/g*dilog(
(d*g-e*f+(g*x+f)*e)/(d*g-e*f))*h+1/2*I*b*Pi*csgn(I*(e*x+d)^n)*csgn(I*c*(e*x+d)^n)^2*i/g*x+1/2*I*b*Pi*csgn(I*c)
*csgn(I*c*(e*x+d)^n)^2*i/g*x+1/2*I*b*Pi*csgn(I*c)*csgn(I*c*(e*x+d)^n)^2/g*ln(g*x+f)*h+1/2*I*b*Pi*csgn(I*(e*x+d
)^n)*csgn(I*c*(e*x+d)^n)^2/g*ln(g*x+f)*h-1/2*I*b*Pi*csgn(I*c*(e*x+d)^n)^3*i/g*x+a*i*x/g-1/2*I*b*Pi*csgn(I*c*(e
*x+d)^n)^3/g*ln(g*x+f)*h-b*ln((e*x+d)^n)/g^2*ln(g*x+f)*f*i+b*n/g^2*dilog((d*g-e*f+(g*x+f)*e)/(d*g-e*f))*f*i-b*
n/g*ln(g*x+f)*ln((d*g-e*f+(g*x+f)*e)/(d*g-e*f))*h-b*i*n*x/g

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ a i {\left (\frac {x}{g} - \frac {f \log \left (g x + f\right )}{g^{2}}\right )} + \frac {a h \log \left (g x + f\right )}{g} + \int \frac {b i x \log \relax (c) + b h \log \relax (c) + {\left (b i x + b h\right )} \log \left ({\left (e x + d\right )}^{n}\right )}{g x + f}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((i*x+h)*(a+b*log(c*(e*x+d)^n))/(g*x+f),x, algorithm="maxima")

[Out]

a*i*(x/g - f*log(g*x + f)/g^2) + a*h*log(g*x + f)/g + integrate((b*i*x*log(c) + b*h*log(c) + (b*i*x + b*h)*log
((e*x + d)^n))/(g*x + f), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {\left (h+i\,x\right )\,\left (a+b\,\ln \left (c\,{\left (d+e\,x\right )}^n\right )\right )}{f+g\,x} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((h + i*x)*(a + b*log(c*(d + e*x)^n)))/(f + g*x),x)

[Out]

int(((h + i*x)*(a + b*log(c*(d + e*x)^n)))/(f + g*x), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (a + b \log {\left (c \left (d + e x\right )^{n} \right )}\right ) \left (h + i x\right )}{f + g x}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((i*x+h)*(a+b*ln(c*(e*x+d)**n))/(g*x+f),x)

[Out]

Integral((a + b*log(c*(d + e*x)**n))*(h + i*x)/(f + g*x), x)

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